A Food Marketing Institute found that 43% of households spend more than $125 a week on...

 

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A Food Marketing Institute found that 43% of households spend more than $125 a week on groceries. Assume the population proportion is 0.43 and a simple random sample of 66 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is between 0.28 and 0.41? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. Answer= (Enter your answer as a number accurate to 4 decimal places.) A Food Marketing Institute found that 43% of households spend more than $125 a week on groceries. Assume the population proportion is 0.43 and a simple random sample of 66 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is between 0.28 and 0.41? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. Answer= (Enter your answer as a number accurate to 4 decimal places.)

Answer rating: 100% (QA)

solution K From the Given dara random sample n 6... View the full answer