Code the problem in scheme using continuation passing style (CPS) and tail recursion. Make sure it can run!

4. everyother takes a list of atoms and returns a list that contains every other atom of the list starting with the first atom. >(everyother(abccdefg))(aceg) 5. everyother* takes a list that may contain sublists. The function returns a list that contains every other element of the input list, and if the element is also a list, then every other element of that sublist is included in the returned list, and so on for each sublists it contains. >( everyother* ' (a(bc(d))((efg)h(((i))()(jk))(mm)))) '(a ((eg)(((i))(j))))