Code using Python, Thank you

HW3_2 According to Archimedes, if a solid that is lighter than a fluid is placed in the fluid, the solid will be immersed to such a depth that the weight of the solid is equal to the weight of the displaced fluid. To find the depth, x, at which the ball floats, this equation must be solved: cVc=w(x2r3x3) Find the floating depth for a cork ball of radius 2cm whose density (c) is one-fifth that of water using secant method to an accuracy of 3 sig figs. [ Use CGS units]. Hints: 1. The density of water (w)=1gm/cc 2. The density of cork (c)=51w 3. Volume of spherical cork of radius r,Vc=34r3