Compile the provided code below by running the program using 20500, 3500, and 10 as the asset cost, salvage value, and useful life, respectively. The depreciation should be $1700.00. Debug the program

//Displays straight-line depreciation

//using the formula: (cost - salvage) / life

//Created/revised by on

#include "stdafx.h"

#include

#include

using namespace std;

//function prototype

double getDepreciation(double, double, int);

int main()

{

double cost = 0.0;

double salvage = 0.0;

double depreciation = 0.0;

int lifeYears = 0;

char another = 'Y';

while (toupper(another) == 'Y')

{

cout << "Asset cost: ";

cin >> cost;

cout << "Salvage value: ";

cin >> salvage;

cout << "Useful life (years): ";

cin >> lifeYears;

depreciation = getDepreciation(lifeYears, cost, salvage);

cout << fixed << setprecision(2) << endl;

cout << "Annual depreciation: $" << depreciation << endl;

cout << endl << "Another calculation (Y/N)? ";

cin >> another;

cout << endl;

} //end while

return 0;

} //end of main function

//*****function definitions*****

double getDepreciation(double price, double endValue, int years)

{

//returns the annual straight-line depreciation

double annualDep = 0.0;

annualDep = (price - endValue) / static_cast(years);

return annualDep;

} //end of getDepreciation function