Question: Compiler Design - Regular Expressions 5. Show that RS !- SR by giving a counterexample (R and S are regular expressions.) 6. Show that (R

Compiler Design - Regular Expressions

Compiler Design - Regular Expressions 5. Show that RS !- SR by

5. Show that RS !- SR by giving a counterexample (R and S are regular expressions.) 6. Show that (R | S)* '= (R* | s*) by giving a counterexample. (R and S are regular expressions.) Also: Is (R | S)* = (R* 1 s*)" ? Yes, no and why

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