Complete the code to output $\text{'}365$ days $=1$ year'. On the next line, output the value of length$\_$days to one digit after the decimal point, followed by $\text{'}$ days $=\text{'},$ and then the value of length$\_$years to five digits after the decimal point, and lastly $\text{'}$ years'

Ex: If the input is $730\mathrm{.}0,$ then the output is:

$365$ days $=1$ year

$730\mathrm{.}0$ days $=2\mathrm{.}00000$ years

Note: $pr{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(f^{\text{'}}\{m{y}_f$loat:$xf{\}}^{\text{'}})$ outputs my$\_$float to $x$ digits after the decimal point.

length$\_$days $=$ float $($input $())$

length$\_$years $=$ length$\_$days $/365$

print$(\text{'}365$ days $=1$ year'$)$

$6$ print$($f$\text{'}\{$length$\_$days:$\mathrm{.}1\}\text{'},$ 'days $=\text{'},$ length years:$\mathrm{.}5\}\text{'},$ 'years'$)$

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