Complete the following code so that it solves this problem: https://projecteuler.net/problem=6Links to an external site. (below)

Sum square difference

Problem 6

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

********************************************************************************************************************************************* 1a) #include

using namespace ?;

int main(){ int N = 100;

int sum = 1;

int ?? = 1;

for (int i = ?? ; i

int solution = ?? * sum - sumsqr ;

cout

cin.get(); }

1b) What is the output of the code in Question 1 for N = 50??

1c) Modify the code in Question 1 so that it works for N = 500. What is the answer to the problem for N = 500?