Question: Complete the following four hypotheses, using = 0.05 for each. 1. Mean sales per week exceed 40.5 per salesperson 2. Proportion receiving online training is

Complete the following four hypotheses, using = 0.05 for each.

  • 1. Mean sales per week exceed 40.5 per salesperson
  • 2. Proportion receiving online training is less than 54%
  • 3Mean calls made among those with no training is at least 140
  • 4. The mean time per call is 14.7 minutes
  • Using the same data set from part A, perform the hypothesis test for each speculation in order to see if there is evidence to support the manager's belief.
  • Compute 99% confidence intervals for the variables used in each hypothesis test and interpret these intervals.
  • Provide a report about the results, distilling down the results in a way that would be understandable to someone who does not know statistics. Clear explanations and interpretations are critical.

Part B: Hypothesis Testing and Confidence Interval

We shall look at four hypotheses of the manager for the set data and evaluate the information with a confidence interval of 99 %.

Hypothesis Test #1

Claim: Mean sales per week exceed 40.5 per salesperson

Step 1: H0a >40.5 (claim)

Step 2: Put information into the spreadsheet

Step 3: This is a right-tailedthe p-valueright-tailedthe p-value test, meaning that the error is on the right side of the distribution

Step 4: Determine p value. The right-sided p-value is 0.000028, which is less than alpha, our significance level.

Level of Significance0.05
Mean under H040.5
n100
Sample Mean43.63
StDev7.44
Use t or z?t

Step 3: This is a right tailed test, meaning that the error is on the right side of the distribution

Step 4: Determine p value. The right-sided p-value is 0.000028, which is less than alpha, our significance level.

SE0.744000
Test statistic4.206989
Left-sided p-value0.999972
Right-sided p-value0.000028
Two-Sided p-value0.000026

Step 5: We reject H0 because p 0 because p a.BecauseHais the claim, we take the manager's claim that mean sales per week exceed 40.5 per salesperson.

Confidence interval for hypothesis #1:

Now we determine if outhe 99% confidence interval reflects our result

Confidence Level99%
n100
Mean43.63
StDev7.44
Use t or z?t
SE0.744000
t-value2.626405
Margin of Error1.954046
Lower Limit41.675954
Upper Limit45.584046

According to our calculation, we are 99% confident that the actual mean sales per salesperson are between 41.68 and 45.58. Therefore, not only are our mean sales > 40.5 per salesperson, but there ia s 99% chance that they are actually between 42 and 46.

Hypothesis Test #2

Claim: Proportion of salesperson receiving online training is less than 54% out of all salesperson.

Step 1: H0> =54%; Ha

Step 2: Put information into the proportion side spreadsheet

Complete the following four hypotheses, using = 0.05 for each. 1. Meansales per week exceed 40.5 per salesperson2. Proportion receiving online training isless than 54%3Mean calls made among those with no training is atleast 1404. The mean time per call is 14.7 minutesUsing the samedata set from part A, perform the hypothesis test for each speculation

Level of Significance Proportion under Ho n Numbe r of Successes 0R Sample Proportion _ 0.430000 0.495076 0.049508 -2.207074 0.013654 0.986346 0.027309

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