Question: Compute dydx for = ( 3 2 ) 2 3 2 y = ( 3 x 2 x ) 2 3 x 2 Select one:

Computedydx for=(32)232y=(3x2x)23x2
Select one:
a.
2(32)(61)(32)22(3x2x)(6x1)(3x2)2
b.
2(32)(61)(32)2(32)2(32)22(3x2x)(6x1)(3x2)2x(3x2x)2(3x2)2
c.
2(32)(32)+2(32)2(32)22(3x2x)(3x2)+2x(3x2x)2(3x2)2
d.
2(32)(61)(32)+2(32)2(32)22(3x2x)(6x1)(3x2)+2x(3x2x)2(3x2)2

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