Compute the derivative of the function

$f(x)=(3x^2\frac{1}{x})(2x^3-5x7)$

Select one:

a$.(6x\frac{1}{x^2})(2x^3-5x7)$

$(3x^2\frac{1}{x})(6x^2-5)$

b$.$

b$.(6x-\frac{1}{x^2})(2x^3-5x7)$

$(3x^2\frac{1}{x})(6x^2-5)$

c$.(6x-\frac{1}{x^2})(6x^2-5)$

d$.(6x1)(2x^3-5x7)(3x^2\frac{1}{x})(6x^2-5)$