Compute the Riemann sum for f(x) = 19 - x on [1, 4] using the partition = {1, 2, 2.5, 3, 4 } and.. . the left endpoint of each subinterval: . the midpoint of each subinterval: Now compute the Riemann sum for f() on [1, 4] using a partition with six equal-width subintervals and... . the right endpoint of each subinterval:Question !: D (x ) = 19 - xx an ( 1 . 4 ] w / P = 2 1 , 3 , 2 . 5 , 3 , 43 Riemann Sum Loft Endpoint Value : +1 (2) + + ( 2 ) 1.5 + + ( 2 .5 ) 15 + + ( 3 ) (1) =19 - ( 1)2 ) (2) 19 - ( 2 ) " ) ( .) + ( 19 - 1 7 .5 7 ) . ) + 19 - ( 3 ) 1 ) = ( 19 - 1 ) ( 3 ) + ( 19 - 4 ) (1 5 ) + ( 19 - 6 . 25 ) ( 5 ) + /19 -9 ) ( " ) = ( 18/ 2 + ( 15 ) (.5) ( 12. 15 ) (5 ) + /10 D (1 ) = 36 + 6 375 + 10 59. 875 Riemann Sum |Midpoint Value : + ( 1 . 5 ) ( 15 ) + + ( 2 . 25 ) ( 2 5 ) + 7 / 2 75 ) ( . 75 ) + 1 ( 3 5 ) ( 5 ) 2+75 : 4 5 25265 3 ty = 7 3/2 - 1. J 4.5/ 2 = 2.75 $5/2= 2,75 1/2=35 AX = 2- 1.5=15 AX = 7.5-7.25=25 AX = B-275= 125 AX= 4-3.5=15 = 19- (15)).5) + (19-2,75)(,25) + (19- (2.75 ) X.25) + 19 ( 15)1) (.5 ) = (19 - 2.25 ) (15) + 19 - 5 . 0625 ) ( 25 ) + ( 19 - 7, 54 25 ) ) ( 125) + ( 19 - 12. 25 ) ( 15 ) = ( 14. 75 ) (.5) + ( 13 , 9375 ) (. 75) + ( 11. 437 5 ) (,25) + (4. 75 ) (.5 ) 8:375 + 3. 48 4375 + 2859375 + 3-375 18 09 375Question ! (contid ) : Riemann Sum Right Endoint w/ 6 equal width subintervals) Ax = ba = 4 - - 3 - 1 15 6 2 IP = 31, 21 2 5 , 3 48 f ( 2) / . 5 ) + 1 ( 2 15 ( 5 ) + f ( 3 ( 1 5 ) + F ( 4 ) 1 5 ) = 19 - (2)1) (15) + 19 - ( 2 . 5 1 2 ) ( 15 ) + 69- ( 3 ) 3 ) (5 ) + ( 19 ( 4 ) ) ( . E) = ( 19 - 4 ) ( 1 5) + ( 1 9 - 6 25 ) ( 5 ) + ( 19 - 9 ) ( 6 ) + (19-8 ) ( . 5 ) = ( 15 ) ( 15 ) + ( 12 75 ) ( 1 5 ) + / 10 ( 5 ) + ( 1 1 ) 1 1 5 7.5 + 4.375 + 5 + 5.5 $ 1/24.3 75