Question: Compute the work done by the vector field F = y x , x vec { F } = langle y - x

Compute the work done by the vector field
F=yx,x\vec{F}=\langle y - x,\ x \rangleF=yx,x
in moving a particle along the circle x2+y2=1x^2+ y^2=1x2+y2=1 from (0,1)(0,1)(0,1) to (1,0)(1,0)(1,0)
Round off answer to one decimal place.

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