Question: Computer A can execute a C program 2 0 times in one second and Computer B can execute the same Cprogram 4 0 times in

Computer A can execute a C program 20 times in one second and Computer B can execute the same Cprogram 40 times in one second. If the MIPS (million instructions per second) rate of Computer A isMIPS_A and MIPS rate of Computer B is MIPS_B, then an engineer concludes that MIPS_B = MIPS_A x 2.Under what conditions is this calculation correct?

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