Question: Computer Architecture And organization Course second part: this is the whole question :) I need all parts to be solved or just e,f, and g

Computer Architecture And organization Course  Computer Architecture And organization Course second part: this is the whole
second part:
question :) I need all parts to be solved or just e,f,
this is the whole question :) I need all parts to be solved or just e,f, and g and g Question 3: For the memory map and registers DR shown

Question 3: For the memory map and registers DR shown in the table below, find the effective address(s) of the following instructions. Flags are D=1 displacement, I=1 indirect. NOTE: Explain every step using your own words. Use computer-based typing and table drawing. BR CR 8FC1 0005 8FCO 8FC2 8FC1 8FC7 8FC2 8FC4 8FC3 8FC5 8FC4 8FC6 8FC5 8FC3 8FC6 8FC1 8FC7 8FC3 e) I=1 Add 8FCO 8FC3 1 f) f) D=1 Add CR 8FC3 Add CR 0003 D=1, base- register addressing Question 3: For the memory map and registers DR shown in the table below, find the effective address(s) of the following instructions. Flags are D=1 displacement, I=1 indirect. NOTE: Explain every step using your own words. Use computer-based typing and table drawing. CR 8FC1 0005 BR 8FCO 8FC2 8FC1 8FC7 8FC2 8FC4 8FC5 8FC3 8FC4 8FC6 8FC5 8FC6 8FC3 8FC1 8FC3 8FC7 a) - 1=1 Add 8FC7 b) - 1=0 Add 8FCO 8FC3 - I=0 Add BR 8FC3 I=1 - d) Add BR 1=1 Add - 8FCO 8FC3 f) D=1 Add CR 8FC3 Add CR 0003 D=1, base- register addressing - Question 3: For the memory map and registers DR shown in the table below, find the effective address(s) of the following instructions. Flags are D=1 displacement, I=1 indirect. NOTE: Explain every step using your own words. Use computer-based typing and table drawing. BR CR 8FC1 0005 8FCO 8FC2 8FC1 8FC7 8FC2 8FC4 8FC3 8FC5 8FC4 8FC6 8FC5 8FC3 8FC6 8FC1 8FC7 8FC3 e) I=1 Add 8FCO 8FC3 1 f) f) D=1 Add CR 8FC3 Add CR 0003 D=1, base- register addressing Question 3: For the memory map and registers DR shown in the table below, find the effective address(s) of the following instructions. Flags are D=1 displacement, I=1 indirect. NOTE: Explain every step using your own words. Use computer-based typing and table drawing. CR 8FC1 0005 BR 8FCO 8FC2 8FC1 8FC7 8FC2 8FC4 8FC5 8FC3 8FC4 8FC6 8FC5 8FC6 8FC3 8FC1 8FC3 8FC7 a) - 1=1 Add 8FC7 b) - 1=0 Add 8FCO 8FC3 - I=0 Add BR 8FC3 I=1 - d) Add BR 1=1 Add - 8FCO 8FC3 f) D=1 Add CR 8FC3 Add CR 0003 D=1, base- register addressing

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