Question: Computer Big O int bar(int n) { int count = 0; for (int i = n; i > 0; i /= 2) { for (int
Computer Big O
int bar(int n) { int count = 0; for (int i = n; i > 0; i /= 2) { for (int j = 0; j < i; j++) { count += 1; } } return count; } Input Format
N, the input to the function, as shown:
10
Constraints
None
Output Format
Print One of the following on its own line :
- O(log n)
- O(n)
- O(n log n)
- O(n^2)
- O(n^3)
- O(2^n)
- O(n^n)
Given code to write solution:
import java.io.*; import java.util.*;
public class Solution {
public static void main(String[] args) { /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */ } }
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