Question: = CONBIN: = proc ( n ) # define the procedure local binary; if type ( n , 'posint' ) then binary : = convert

=CONBIN:=proc(n)# define the procedure
local binary;
if type(n, 'posint') then binary := convert(n, binary); # It first checks if the input is a positive integer.'
return cat ('The integer ',n,' converts into its binary equivalent', binary);
#If it is, it converts the integer to binary using the convert function and concatenates the result into a sentence.
else return 'Input must be a positive integer'; end if; #If the input is not a positive integer, it returns an error message.
end proc;
CONBIN := proc (n)
local binary;
if type(n, 'posint') then
binary := convert(n, binary); return cat ('The * integer', n, 'converts ** into ** its * binary * equivalent', binary)
else
return 'Input * must * be*a* positive * integer'
end if
end proc
CONBIN(10); #if the input is a positive integer, say 10, the procedure will convert it to binary equivalent of 1010
The*integerl Oconverts its *binary *equivalent 1010
CONBIN(-10)# if the input is a negative integer, say -10, then there will be an error message.
Input must be a positive integer
#CAN YOU HELP? I want the output of COBIN(10) BE
The integer 10 converts into its binary equivalent of 1010. instead of
The ?** integer 10 converts ** into ** its ** binary * equivalent1010. i.e. remove the stars and add space
 =CONBIN:=proc(n)# define the procedure local binary; if type(n, 'posint') then binary

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