Question: Confidence Interval to estimate a population's standard deviation A jar of olive oil is supposed to contain 32 ounces. The filling machine experiences slight deviations


Confidence Interval to estimate a population's standard deviation A jar of olive oil is supposed to contain 32 ounces. The filling machine experiences slight deviations (sometimes too much, sometimes too little), and it is monitored by a quality control manager. In a random sample of ten (10) jars, the content of each was weighed: 32.21 ounces 31.25 31.36 31.84 31.87 31.51 32.16 31.51 32.28 32.53 Check: mean = 31.852 std.dev. s = ? Round s to three decimal places. Do all parts (a) (c): (a) Construct a 95% confidence interval for the population standard deviation . You may assume the population is normally distributed. Below, I've provided the formulas for lower and upper bounds of variance o to get you started. dj Critical Value S 02 S df Critical Value for 025 for 975 (b) Interpret the confidence interval, "We are 95% confident that ...." (c) The filling machine will have to be shut down and recalibrated if the estimated population standard deviation is greater than .250 ounce. Will the machine be shut down for maintenance? (Yes/No)
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
