Question: Confidence Intervals. Part 1.It is often difficult to find the exact mean average of a large population of data.We use confidence Intervals to estimate where
Confidence Intervals.
Part 1.It is often difficult to find the exact mean average of a large population of data.We use confidence Intervals to estimate where we think the true mean lies.Discuss the advantages of using a confidence interval. Give an example of a large population of data that is suited to a confidence interval estimate- in other words, it would be very hard to find the exact true mean of the data.
- It is often difficult to find the exact mean of a large population of data. We use confidence Intervals to estimate where we think the true mean lies. Discuss the advantages of using a confidence interval. Give an example of a large population of data that is suited to a confidence interval estimate. In other words, provide an example where it would be very hard to find the exact true mean of the data. Remember to discuss the ability to determine the sample mean and standard deviation; access to a large sample size; and the desired confidence level. You need to incorporate these topics within your response to Part I.
Part 2. Completethe assignment below.
- You need to complete the provided attachment within original discussion board instructions.
Remember that I expect you to show all work which includes the identification of your sample mean, sample standard deviation, sample size, degrees of freedom, and confidence level. You should also identify the margin of error. Provide the above formula within the work that you show where all components are clearly identified. I need to see all of your calculations. At the end, make one grand conclusion where you will properly use your confidence interval results to make an informed decision regarding the true population mean.
This is an example of a correct way to complete this:
Part 1:
My example and explanation for the first part of this discussion board response has to do with the central requirement of this post because I used a real-world example from a peer-reviewed article that was published in 2017 to describe the use of confidence intervals, standard deviations, means, and sample sizes in an experiment. It would be difficult to find the exact true mean of the data in my example because notallCanadian or American citizens (between the ages of 18 and 60) would be willing to participate in the survey that the creators made. The results for the online Qualtrics Panels will be based on the responses from the people who met the criteria and who were willing to participate. The exact true mean is either impossible to obtain or prohibitively time consuming/costly. The creators would struggle to get everyone to participate in the survey, so they prevented the hassle by choosing a certain amount of people who were able to do so, rather than worrying about havingeveryoneanswer the multiple choice/open-ended questions.
Part 2:
The sample size value is 4 (it is between 4 and 10), the sample mean value (is 24 (it is between 10 and 80), and the sample standard deviation value is 18 (it is between 3 and 20). I discovered the df for the problem, so that I could use that information and understand the Appendix Table IV answer. I managed to calculate the df by subtracting 1 from 4 (because the equation was df=n-1) to get 3. After that, I calculated "a" by subtracting 0.90 from 1, which equalled 0.10. I then divided 2 by my 10 to get 0.05. I used the Appendix Table IV by looking at column T0.05and row 8, which led me to 2.353 (T-value). I discovered the margin of error by performing Margin of Error = (t-value)s/n. The equation was 24 (2.353)(18/4). I did this calculation (2.353)(18/4) to get 21.177 (the margin of error). Lastly, after performing all of the calculations from that specific equation, I was able to discover that 24+ 21.177 = 45.177 and 24 - 21.177 = 2.823. The confidence Interval for population mean is between 2.823 and 45.177. Overall, the smaller sample size (4) resulted in a wider confidence interval (2.823-45.177) with a larger margin of error (21.177).
Thank you,
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