Consider a $2\mathrm{.}00L$ solution of $0\mathrm{.}015MAgN{O}_3.$ How many grams of precipitate will be produced when excess $K_{2}C{O}_3$ is added it to$?K_{2}C{O}_3(aq)+2AgN{O}_3(aq)-A{g}_{2}C{O}_3(s)+2KN{O}_3(aq)$ A$)4\mathrm{.}1g$ B$)11g$ C$)2\mathrm{.}0g$ D$)8\mathrm{.}2g$ E$)5\mathrm{.}5$