Question: Consider a ????????????????????????(50, ????????) from the population ???????? = {service transactions over the past year at Bewilders Bank}. Let ???????? = time to service at

Consider a ????????????????????????(50, ????????) from the population ???????? = {service transactions over the past year at Bewilders Bank}. Let ???????? = time to service at Bewilders Bank. It is known that the ????????????????????????????????(????????: ????????) is skewed to the right with a mean of 7.2 and standard deviation 8.4 minutes. Even with this skewness, it turns out that the sample average ????????, the average time to service for a ????????????????????????(50, ????????), has an approximate Normal distribution with mean 7.2 and standard deviation 8.4/ 50 = 1.19. (This approximate Normality of a sample average based on a large sample size holds quite generallysee the Central Limit Theorem in Sec 9.1.) (a) What are the approximate chances that the sample average time to service is greater than 8 minutes? (b) Would you be surprised if the average time to service for 50 randomly sampled customers is less than 4 minutes? Explain. (c) What are the values of ????????????????????????????????( ???????? ????????????????????????(50, ????????)) and ????????????????(????????: ????????????????????????(50, ????????))? (d) Given empirical interpretations of the two process parameters of part (c). 51

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