Consider a computer that uses 8 bits to represent floating point numbers, 1 bit for the sign s, 3 bits for the exponent c (c e 3), and 4 bits for fractional part f In terms of s, e, and f, the base 10 numbers are given by x ( 1)' 2 (1 f), c is non negative, and 0 f 1 This is the same design as the IEEE floating point representation with a much shorter machine word length (a) What are the smallest and largest positive (non zero) numbers that can be represented accurately (without any chopping rounding error) on this computer (b) How many numbers can be accurately (without any chopping rounding error) represented on this computer (c) By changing c to 4 bits and f to 3 bits, what do you gain and what do you lose

Question: Consider a computer that uses 8 bits to represent floating-point numbers, 1 bit for the sign s, 3 bits for the exponent c (c

Consider a computer that uses 8 bits to represent floating-point numbers, 1 bit for the sign s, 3 bits for the exponent c (c =e +3), and 4 bits for fractional part f. In terms of s, e, and f, the base 10 numbers are given by x = (-1)' 2 (1+ f), c is non-negative, and 0 f

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