Consider a five$-$sided closed polygon traverse. The azimuth of side

$AB$ is fixed at $218{59}^{\text{'}}{30}^{\text{'}\text{'}}.A=132{47}^{\text{'}}{06}^{\text{'}\text{'}},B=108{46}^{\text{'}}{18}^{\text{'}\text{'}},$

$C=107{19}^{\text{'}}{37}^{\text{'}\text{'}},D=81{50}^{\text{'}}{36}^{\text{'}\text{'}},E=109{16}^{\text{'}}{18}^{\text{'}\text{'}}.($Note: line

$BC$ bears SE$.)$ The lengths of the sides $($in feet$)$ are as follows

$AB=202\mathrm{.}74,BC=283\mathrm{.}87,CD=498\mathrm{.}37,DE=320\mathrm{.}33,$ and

$EA=380\mathrm{.}78.$ The coordinates of station A are $x=20,000\mathrm{.}00ft$

and $Y=15,000\mathrm{.}00ft.$

Part A

Use the coordinate method to compute the area enclosed by the traverse above.

Express your answer in feet squared to two significant figures. Note: Traverse does not need to be adjusted to determine the correct answer.