Question: Consider a flat ceiling that is built around 3 8 - m m 9 0 - m m wood studs with a center - to

Consider a flat ceiling that is built around 38-mm90-mm wood studs with a center-to-center distance of 400mm. The lower part of the ceiling is finished with 13-mm gypsum wallboard, while the upper part consists of a wood subfloor )=(0.166m2*CW, a 13-mm plywood, a layer of felt )=(0.011m2*CW, and linoleum W). Both sides of the ceiling are exposed to still air. The air space constitutes 82 percent of the heat transmission area, while the studs and headers constitute 18 percent. Determine the winter R-value and the U-factor of the ceiling assuming the 90-mm-wide air space between the studs. Extra needed information can be found in Table 3-8 below.
TABLE 3-8
(below i provided R values)
outside surface still air: R=0.030 m2\deg C/W
linoleum: R=0.009 m2\deg C/W
plywood: R=0.11 m2\deg C/W
wood subfloor: R=0.166 m2\deg C/W
plane air space: R=0.16 m2\deg C/W
gypsum: R=0.079 m2\deg C/W
inside surface still air: R=0.12 m2\deg C/W
Consider a flat ceiling that is built around 3 8

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