Question: Consider a piecewise-defined function h : IR - R defined by the rule h(x) = 3x3 -57x2 +366x - 749, & SA, 6x +7, r


Consider a piecewise-defined function h : IR - R defined by the rule h(x) = 3x3 -57x2 +366x - 749, & SA, 6x +7, r > A, where A is some real number. (a) Consider the following Maple output: > k := x -> (3*x43-57*x* 2+366*x-749) - (6*x+7) ; k:= x-3x3 -57x2 +360x - 756 > factor (k(x) ) ; 3(x - 7)(x -6)2 There are two values A = p1 and A = po that make h continuous on IR. Enter these values as a set. Syntax advice: Enter your set using Maple syntax for sets. For example, the set {0, 1} may be written as {0, 1} {P1, p2} = Briefly explain why these values for A make h continuous on IR. Essay box advice: In your explanation, you don't need to use exact Maple syntax or use the equation editor, as long as your expressions are sufficiently clear for the reader. For example, you can write . A as'A', . x2 + 2x + 1as 'x^2 + 2x + 1', . h(x) as 'h(x)'(b) Observe that h is differentiable everywhere Click for List Briefly justify your answer in the box below. for A = p1 or A = po, but not both : t: for no real values A Equation Editor for all A E R 2 for A = p1 and A = P2
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
