Consider a rational function $f$ that satisfies the following conditions.

$\underset{x+-}{lim}f(x)=0,\underset{x0}{lim}f(x)=-,f(3)=0,$

$\underset{x{9}^{-}}{lim}f(x)=,\underset{x{9}^{+}}{lim}f(x)=-,$

Excellent!

Good job.

Which $of$ the following must $be$ true?

The degree $of$ the numerator $is$ greater than the degree $of$ the denominator.

The degrees $of$ the numerator and the denominator are equal.

The degree $of$ the denominator $is$ greater than the degree $of$ the numerator.

That's $it!$

Find $an$ equation for $f.$

$f(x)=$