Consider a router that interconnects three subnets: Subnet 1, Subnet 2, and Subnet 3. Suppose all of the interfaces in these subnets are required to have the prefix 134.39.176.0/22. Also suppose that Subnet 1 needs to support at least 450 interfaces, Subnet 2 needs to support at least 200 interfaces, and Subnet 3 needs to support at least 160 interfaces. Provide three network addresses (a.b.c.d/x) that satisfy these constraints.

I got the correct answer for this but i dont understand why. Can someone help me to explain?

required prefix: 134.39.176.0/22 134.39.10110000.00000000/22

network: 134.39.101100xx.xxxxxxxx =2^10 = 1024 interfaces

134.39.101100xx.xxxxxxxx

134.39.1011000x.xxxxxxxx = 2^9 = 512 interfaces --> subnet 1

134.39.1011001x.xxxxxxxx = 2^9 = 512 interfaces --> split

134.39.10110010.xxxxxxxx = 2^8 = 256 interfaces --> subnet 2

134.39.10110011.xxxxxxxx = 2^8 = 256 interfaces --> subnet 3

subnet 1: 134.39.176.0/23 or 134.39.10110000.00000000/23

subnet 2: 134.39.178.0/24 or 134.39.10110010.00000000/24

subnet 3: 134.39.179.0/24 or 134.39.10110011.00000000/24