Consider a system built on a $48MHz$ processor with a main loop and an interrupt which occurs at a

$10kHz$ frequency. Assume the ISR take $14\mathrm{.}9$us to execute and there is a total of $1$us of response and

return time overhead.

$1\mathrm{.}1.$ What percentage of the processor's time is spent in interrupt response and return overhead?

$1\mathrm{.}2.$ What percentage of the processor's time is left for the main loop to execute?

$1\mathrm{.}3.$ If the main loop requires $37ms$ of computation to execute one iteration, what is the minimum main loop

update rate $($in $Hz)?$