Consider a uniform square plate with a central square hole and material of mass density $7800k\frac{g}{m^3}.$ For $a=650mm$ and $t=12mm,I_{zz}$ is best given by

$($a$.)2\mathrm{.}61kg*m^2$

b$.,6\mathrm{.}17kg*m^2$

$=7800$

c$.4\mathrm{.}10kg*m^2$

d$.,1\mathrm{.}58kg*m^2$

$I_{22}=\frac{1}{2}74518({650}^2+{650}^2)$

$-\frac{1}{2}76518({325}^2+{325}^2)$

$538814$

$134704$

$q,$

$7800*9\mathrm{.}81,4\mathrm{.}12$