Question: Consider alphabet Sigma = 0 , 1 and language L 0 1 = w in Sigma : w = 0 ^ n 1

Consider alphabet \Sigma =0,1 and language L01=w in \Sigma : w =0^n1^n for some nonnegative n in Z. Prove or disprove that for each language L over \Sigma , if L \cap L01= and L is regular, then L is finite.

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