Question: Consider an AR(1) process X = X-1+Z with 50 observations {XX50} Given an expression of the log-likelihood function () of X. (X-X-1))-(1-) 50 0

Consider an AR(1) process X = X-1+Z with 50 observations {XX50} Given an expression of the log-likelihood function () of X. (X-X-1))-(1-) 50 0 (0) = -In (50) +in, O (6) = In (50) +In x(1-6) +2(X-X-11+(1-) 50 ((*) = -(50) +[Xx;(1-6)+22(X-4X4-1) - / - O 50 (*) = -In(50) +In x(1-6) + 2(x,-X,-1)-50 (1-8) (0) = -In(50) +In +inx +[X1-23 +24-04-2)-501-89 (0) = In(50) 50) + X(1-0)- 2, 05-05-0-241-91 -In(1-)
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