Consider an n$-$type Si rectangular bar with a length L$=1$L$=1$ cmcm$,$ width w$=0\mathrm{.}5$w$=0\mathrm{.}5$ mmmm and thickness t$=5\mathrm{.}0$t$=5\mathrm{.}0$ mm$.$

The top surface $(1$ cm $0\mathrm{.}5$ mm$)$ is then uniformly illuminated by monochromatic light at $1\mathrm{.}3$ eV with power density of $0\mathrm{.}30\mathrm{.}3$ W$/$cm$2$W$/$cm$2.$ Assume that Nd$=1014$Nd$=1014$ cm$3$cm$3,$ n$=1400$n$=1400$ cm$2/$V$$scm$2/$V$$s$,$ p$=500$p$=500$ cm$2/$V$$scm$2/$V$$s$,$ ni$=1\mathrm{.}451010/$cm$3$ni$=1\mathrm{.}451010/$cm$3$ is much less than NdNd$,$ $($quantum efficiency$)=0\mathrm{.}8,$ $($absorption coefficient$)=1103/$cm$1103/$cm and n$=$p$=1106$sn$=$p$=1106$s$.$

Calculate the resistance under illumination. Your answer should be in ohms, $.$