Consider function $f(x)=\frac{x^2-9}{x3}.$

Determine whether $f(x)$ has a $($dis$)$continutiy at $x=-3$ by evaluating the following:

$\underset{x-3^{-}}{lim}f(x)=$

$$

$\underset{x-3^{}}{lim}f(x)=$

$$

$0^{}$

$f(-3)=$

Therefore, $f(x)$ has a removable discontinuity

at $x=-3.$