Question: Consider L = { abwba: w in Sigma * but does not contain the substring ba } over Sigma { a , b

Consider L ={abwba: w in \Sigma * but does not contain the substring ba} over \ Sigma {a, b, c, d}.1. Show that L is a regular language by drawing a DFA for it, with the DFA having as few states as you can. 2. Draw an NFA for L with as few states as you can. 3. Convert the NFA to a GNFA. 4. Convert the GNFA to an RE ( Regular Expression) using the procedure discussed in class. Show the steps. You may, but are not required to, shorten intermediate REs using identities like R = and \ epsi R = R and R \cup = R to reduce expression swell

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