Question: Consider the 4x5 matrix A= 0 1 0 -2 0 0 1 1 -2 3 0 0 0 0 1 0 0 0 0 0

Consider the 4x5 matrix A=

0 1 0 -2 0
0 1 1 -2 3
0 0 0 0 1
0 0 0 0 0

a) Show that v = [-1,1,0,0]^T lies in C(A), the column space of A. Is there more than one way to write v as a linear combination of the columns of A? Explain.

b) Find the basis for the null space of A and Compute dim N(A).

c) Write all solutions to the linear sustem Ax = [-1,1,0,0]^T.

d) Does the set of solutions to the equation Ax = [-1,1,0,0]^T form a subspace of R^5? Explain

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