Question: Consider the above Binary Tree, what will be the result of running the following code: sub P(TreeNode) Output(TreeNode.value) If LeftPointer(TreeNode) != NULL Then P(TreeNode.LeftNode) a)

Consider the above Binary Tree, what will be the result of running the following code: sub P(TreeNode)

Output(TreeNode.value)

If LeftPointer(TreeNode) != NULL Then

P(TreeNode.LeftNode)

a) F, B, A, D, C, E, G, I, H

b) F, B, A, D, C, E, G, H, I

c) B, F, A, D, C, E, G, I, H

d) F, B, A, D, E, G, I, H

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