Consider the absorber$-$stripper system illustrated on the next page. The feed containing $30\%C{O}_2,10\%H_{2}S$ and

an inert gas $(I)$ is scrubbed of $H_{2}S$ and $C{O}_2$ by using a solvent to selectively absorb the $H_{2}S$ and $C{O}_2.$ The resulting

stream $(5)$ in which the pressure is reduced, and as a result some of the $C{O}_2,H_{2}S$ and some

of the solvers ar soparaded as an overhead stream $(6).$ The remaining solution is split, with half being returned

to the absorber and half to the stripping unit. In the stripping unit, the pressure is reduced further, resulting in an

overhead stream $(10)$ comprising $30\%$ solvent and an unknown amount of $C{O}_2$ and $H_{2}S.$ The bottoms stream from

the stripper $(9),$ comprising pure solvent, is recycled back to the absorber after mixing with some additional pure

solvent which makes up for the solvent lost in the flash and stripper overheads. The absorber is operated so that

the outlet overhead stream $(2)$ from the unit contains no $H_{2}S$ and only $1\%C{O}_2.$ The stripper feed solution $(8)$

contains $5\%C{O}_2$ and the overhead from the flash $(6)$ contains $20\%$ solvent. Finally, the flash is operated so that

$25\%$ of the $C{O}_2$ and $15\%$ of the $H_{2}S$ in stream $(1)$ are released in the overhead $(6).$

Using degree$-$of$-$freedom analysis, determine the solution order, and solve for all of the unknowns $($assuming feed

$\{$:$m_1=100\frac{kg}{h}).$ All percentages are on a mass basis.