Consider the area between the graphs a + 3y = 32 and x + 8 = y2. This area can be computed in two different ways using integrals First of all it can be computed as a sum of two integrals ['s(a)da + ( o(x) da where a = , 6 , C = and f(ac) = g() = Alternatively this area can be computed as a single integral [ n(y) dy where a : B = and h(y ) = Either way we find that the area isFind the area of the region bounded by the graphs ofy = m3 and y = 3m using integration. Determine the area by integrating over the xaxis or y aXis, Whichever seems more convenient. Answers should be exact. As a suggestion, graph the equations so you can see the region for which you are solving for the area. Area of region A =