Question: Consider the area between the graphs x+3y = 31 and x+9=y^2. This area can be computed in two different ways using integrals. Integral from a

Consider the area between the graphs x+3y = 31 and x+9=y^2. This area can be computed in two different ways using integrals.

Integral from a to b of f(x) dx + integral from b to c of g(x) dx:

Solve for a, b and c and find the value of f(x) and g(x) respectively.

The area can also be computed as a single integral:

Integral from alpha to beta of h(y) dy

Solve for alpha, beta, and find the value of h(y).

Either way we find that the area is?

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