Consider the base hydrolysis of an ester.

$)-($where $R$ and $R^{\text{'}}$ represent organic groups$).$

The kinetics of this reaction, for a particular ester, were studied using the isolation method.

When $[O{H}^{-}]>>[R\frac{C}{O}O{R}^{\text{'}}]$ a pseudo$-$rate law can be posed:

$-\frac{d[R\frac{C}{O}O{R}^{\text{'}}]}{dt}=k^{\text{'}}[R\frac{C}{O}O{R}^{\text{'}}{]}^n$

With initial concentrations:

$[O{H}^{-}{]}_0=0\mathrm{.}900M$

$[R\frac{C}{O}OR{]}_0=0\mathrm{.}0010M,$

a plot of $ln[R\frac{C}{O}O{R}^{\text{'}}]$ versus $t$ gave a straight line with slope $=-2\mathrm{.}85{10}^3{s}^{-1}$ and $y-$intercept $=-6\mathrm{.}91.$

What is the order $"n"?$

$n=$

What is the corresponding pseudo rate constant $k^{\text{'}}?($include appropriate units$)$

$k^{\text{'}}=$

$1$ pts

Tries $\frac{0}{5}$

When $[O{H}^{-}]<mi\; id="EditorElement\_3387476">[</mi><mi\; id="EditorElement\_3387450">R</mi><mfrac\; id="EditorElement\_3387463"><mrow\; id="EditorElement\_3387456"><mi\; id="EditorElement\_3387453">C</mi></mrow><mrow\; id="EditorElement\_3387462"><mi\; id="EditorElement\_3387459">O</mi></mrow></mfrac><mi\; id="EditorElement\_3387465">O</mi><mtext\; id="EditorElement\_3387467"></mtext><msup\; id="EditorElement\_3387475"><mrow><mi\; id="EditorElement\_3387468">R</mi></mrow><mrow\; id="EditorElement\_3387474"><mi\; id="EditorElement\_3387471">\text{'}</mi></mrow></msup><mi\; id="EditorElement\_3387477">]</mi>$ a pseudo$-$rate law can be posed:

$-\frac{d[O{H}^{-}]}{dt}=k^{\text{'}\text{'}}[O{H}^{-}{]}^m$

With initial concentrations:

$\{\begin{array}{c}\text{:}[O{H}^{-}{]}_0=0\mathrm{.}0015M\end{array}$

$\{\begin{array}{cc}\text{:}[R\frac{C}{O}O& R{]}_0=0\mathrm{.}600M\end{array}$

a plot of $ln[O{H}^{-}]$versus $t$ gave a straight line with slope $=-1\mathrm{.}90{10}^3{s}^{-1}$ and $y-$intercept $=-6\mathrm{.}50.$

What is the order $"$m$"?$

$m=$

What is the corresponding pseudo rate constant $k^{\text{'}\text{'}}?($include appropriate units$)$

$k^{\text{'}\text{'}}=$

$1pts$