Question: Consider the below C code snippet: int a[3]; for (int i = 0; i < 3; i++) { a[i] = a[i] & 0xAB; } (1).

Consider the below C code snippet:

int a[3];

for (int i = 0; i < 3; i++)

{

a[i] = a[i] & 0xAB;

}

(1). Write the corresponding MIPS assembly code. Assume that the base address of the array a is 0x23BDF003.

(2). If the array a is initialized as {0, 1, 2}, what are the elements of the array a after the above code is run?

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