Consider the code snippet below:

int main$()$

$\{$

Shape$*$ shapes$[$NUM$\_$OBJECTS$]$;

shapes$[0]=$ new Circle$(0,0,100,150)$;

shapes$[1]=$ new Rectangle$(200,200,50,100)$;

shapes$[2]=$ new Circle$(300,50,250,250)$;

shapes$[3]=$ new Rectangle$(100,350,200,150)$;

for $($int i $=0$; i $<$ NUM$\_$OBJECTS; i$++)$

$\{$

shapes$[$i$]->$draw$($draw$\_$area$)$;

$\}$

for $($int i $=0$; i $<$ NUM$\_$OBJECTS; i$++)$

$\{$

delete shapes$[$i$]$;

$\}$

$\}$

In order for pointers to the two different objects Circle and Rectangle to be put into the same array $($shapes$),$ what must be true?