Question: Consider the code that follows. What does it do ? String value = two; try { int num = Integer.parseInt ( value ) ; System.out.println
Consider the code that follows. What does it do
String value "two";
try
int num Integer.parseIntvalue;
System.out.printlnValid integer";
catchNumberFormatException e
System.out.printlnInvalid integer";
Group of answer choices
It prints Valid integer to the console.
It prints Valid integer and then Invalid integer to the console.
It prints Invalid integer to the console.
This code wont compile.
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