Consider the curve $C$ defined by

$y=f(x)=\frac{cos(x)}{2-sin(x)}$

for $0x\frac{}{2}.$

It can be shown that

$y^{\text{'}}(x)=\frac{1-2sin(x)}{(2-sin(x){)}^2}$

Hence, $y^{\text{'}}(x)=0,$ when $x=\frac{}{6}.$ Find the minimum and maximum values of $y,$ and the points where these occur, for $0x\frac{}{2}.$