Question: Consider the curve f ( x ) = ( - 1 / 3 x - 1 ) square root ( - 2 x - 9

Consider the curve f(x)=(-1/3 x -1) square root (-2x -9)
and the line g(x)=-x+7
Find the equation of a tangent line to f(x) that is parallel to g(x). Give your equation in the form y = mx+b

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