Question: Consider the definite integral I[cos x2] = We cannot calculate its exact value but we can compute accurate approximations to it using Th[cos x2]. Let

Consider the definite integral

I[cos x2] = We cannot calculate its exact value but we can compute accurate approximations to

it using Th[cos x2]. Let

q(h) = Th/2[cos x2] Th[cos x2] . (4) Th/4[cos x2] Th/2[cos x2] Consider the definite integral I[cos x2] = We cannot calculate its exactIn Python 3.7 please

3. Consider the definite integral 0 We cannot calculate its exact value but we can compute accurate approximations to it using Th(cos 21. Let h COS h/4 COS T (a) Using your code, find a value of h for which q(h) is approximately equal to 4. (b) Get an approzimation of the error, Icos 2] Th[cos a2], for that particular value of h (c) Use this error approximation to obtain the extrapolated, improved, approximation COS T (d) Explain why Sh[cos z2 is more accurate and converges faster to I[cos 2] than Th[cos r 3. Consider the definite integral 0 We cannot calculate its exact value but we can compute accurate approximations to it using Th(cos 21. Let h COS h/4 COS T (a) Using your code, find a value of h for which q(h) is approximately equal to 4. (b) Get an approzimation of the error, Icos 2] Th[cos a2], for that particular value of h (c) Use this error approximation to obtain the extrapolated, improved, approximation COS T (d) Explain why Sh[cos z2 is more accurate and converges faster to I[cos 2] than Th[cos r

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