Consider the differential equation $\frac{dy}{dx}-2y=e^{4x}.$

i$.)$ Which of these is the general solution of this equation?

$y=\frac{1}{2}{e}^{4x}C$

$y=\frac{C{e}^{6x}}{2}$

$y=e^{2x}C$

$y=\frac{1}{2}{e}^{4x}C{e}^{2x}$

ii$.)$ What choice of the arbitrary constant in the general solution ensures that the solution satisfies the initial condition $y(0)=3?$

$c=$

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