Question: Consider the differential equation ( x - 1 ) y ' ' - 2 x y ' + ( x + 1 ) y =

Consider the differential equation
(x-1)y''-2xy'+(x+1)y=0,x>1
The function y1(x)=ex is one of solutions.
Choose the function y2 such that y1 and y2 form fundamental set of solutions.
y2(x)=(x-1)3ex
y2(x)=(x-1)2ex
y2(x)=x-1
y2(x)=(x-1)2Consider the differential equation
(x-1)y''-2xy'+(x+1)y=0,x>1
The function y1(x)=ex is one of solutions.
Choose the function y2 such that y1 and y2 form fundamental set of solutions.
y2(x)=(x-1)3ex
y2(x)=(x-1)2ex
y2(x)=x-1
y2(x)=(x-1)2Consider the differential equation
(x-1)y''-2xy'+(x+1)y=0,x>1
The function y1(x)=ex is one of solutions.
Choose the function y2 such that y1 and y2 form fundamental set of solutions.
y2(x)=(x-1)3ex
y2(x)=(x-1)2ex
y2(x)=x-1
y2(x)=(x-1)2
Consider the differential equation ( x - 1 ) y '

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