Question: Consider the equation below. ( If an answer does not exist, enter DNE. ) f ( x ) = x 3 1 2 x 2

Consider the equation below. (If an answer does not exist, enter DNE.)
f(x)= x312x227x +2
(a)
Find the interval(s) on which f is increasing. (Enter your answer using interval notation.)
(,1)(9,)
Find the interval(s) on which f is decreasing. (Enter your answer using interval notation.)
(1,9)
(b)
Find the local minimum and maximum values of f.
local minimum value
478
local maximum value
22
(c)
Find the inflection point.
(x, y)=
4,228
Find the interval(s) on which f is concave up.(Enter your answer using interval notation.)
(4,)
Find the interval(s) on which f is concave down. (Enter your answer using interval notation.)
(,4)

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