Consider the equilibrium below. Initially 72.40 grams of SbCl 5 were placed in a 1.0 L vessel
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Question:
Consider the equilibrium below. Initially 72.40 grams of SbCl 5 were placed in a 1.0 L vessel at 298 K. The result was a total pressure of 8 bar in the vessel at equilibrium. What is K for this reaction?
SbCl 5 (g) ⇌ SbCl 3 (g) + Cl 2 (g)
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