Question: Consider the fallowing truth table for M=f(A, BC). A B C M 0 0 0 1 0 0 1 0 0 1 0 0 0
Consider the fallowing truth table for M=f(A, BC).
| A | B | C | M |
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 0 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 1 |
| 1 | 1 | 1 | 1 |
Give (a) a straightforward implementation of the circuit for that truth table (by designing multiplications of addition) and do the same problem by using only NAND Gates.
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